7(4x^2)=10

Solution for 7(4x^2)=10 equation:

7(4x^2)=10

We move all terms to the left:

7(4x^2)-(10)=0

a = 74; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·74·(-10)
Δ = 2960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2960}=\sqrt{16*185}=\sqrt{16}*\sqrt{185}=4\sqrt{185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{185}}{2*74}=\frac{0-4\sqrt{185}}{148}
=-\frac{4\sqrt{185}}{148}
=-\frac{\sqrt{185}}{37}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{185}}{2*74}=\frac{0+4\sqrt{185}}{148}
=\frac{4\sqrt{185}}{148}
=\frac{\sqrt{185}}{37}
$